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NO.1 Table TAB_A and index TABA_IDX were created by executing these SQL statements:
If this SQL statement is executed after 100,000 records have been inserted into table TAB_A: ALTER
INDEX taba_idx COMPRESS NO;
Which statement correctly describes what will happen to index TABA_IDX?
A. The index will be uncompressed immediately.
B. The index will remain compressed until it is REORGed.
C. The index will remain compressed until the COMPRESS attribute for table TAB_A has been set to NO.
D. The index will remain compressed until the COMPRESS attribute for table TAB_A has been set to NO
and both the table and the index have been REORGed.
Answer: B
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NO.2 Which of the following SQL statements will return monitoring information of tables in the DB2USER
schema that begin with the letter 'A'?
A. SELECT * FROM mon_get_table('DB2USER','A%',-2)
B. SELECT * FROM TABLE(mon_get_table('DB2USER','A%',-2))
C. SELECT * FROM mon_get_table('DB2USER',",-2) WHERE TABNAME LIKE 'A%'
D. SELECT * FROM TABLE(mon_get_table('DB2USER','',-2)) WHERE TABNAME LIKE 'A%'
Answer: D
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NO.3 Which of following is true when decomposing multiple XML documents?
A. It is possible to decompose multiple XML documents stored in a binary column or in an XML column.
B. It is not possible to decompose multiple XML documents stored in a binary column or in an XML
column.
C. It is possible to decompose multiple XML documents stored in a binary column but not in an XML
column.
D. It is possible to decompose multiple XML documents stored in a XML column but not in an binary
column.
Answer: A
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NO.4 When storing XML data in a DB2 database, which statement is valid.?
A. A table with an XML column can be defined in a non-Unicode database.
B. A table with an XML column can only be defined in a Unicode database.
C. A table with an XML column can be defined in a non-Unicode database but the table containing the
XML column will be stored in Unicode.
D. A table with an XML column can be defined in a non-Unicode database but the database must be
converted to Unicode before the XML columns can be used.
Answer: A
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NO.5 If table TAB_A is created as follows:
Assuming the cardinality of the columns is the same, which statement will create an index that will benefit
the most from compression?
A. CREATE INDEX taba_idx ON tab_a (c2)
B. CREATE INDEX taba_idx ON tab_a (c4)
C. ALTER TABLE tab_a ADD PRIMARY KEY (c1)
D. CREATE UNIQUE INDEX taba_idx ON tab_a (c2)
Answer: A
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NO.6 Given the following DDL statements:
What is the end result of the CREATE INDEX statement?
A. TBSP21 and TBSP22 will each contain one local index.
B. INDEX_TS will contain one non-partitioned index since the create index command is missing the
PARTITION keyword.
C. TBSP11 and TBSP12 will each contain one local index since the local indexes will physically reside in
the same table space as the related data.
D. TBSP21 will contain one index because NEW_IDX is not partitioned and will automatically go into the
first index partition listed in the create table statement.
Answer: A
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NO.7 Click on the Exhibit button
Given the following DDL statements:
If COL2 contains XML documents similar to the one shown in the scenario, what is the end result of the
CREATE INDEX statement?
A. An error will be returned because it is not possible to create an index for an XML column like COL2.
B. TBSP11 and TBSP12 will each contain one local index for XML_INDEX since the local indexes will
physically reside in the same table space as the related data.
C. An error will be returned because it is not possible to include more than one column as part of the
CREATE INDEX statement when one of the columns is of type XML.
D. A non-partitioned index will be created in table space TBSP21 since the INDEX IN clause of the table
definition is ignored and XML_INDEX will automatically be created within the first index partition listed in
the create table statement.
Answer: C
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NO.8 If table TAB_A has just been created as follows:
Which command will create a compression dictionary for table TAB_A?
A. DELETE FROM tab_a
B. REORG TABLE tab_a
C. UPDATE tab_a SET c1 = c1*1.1
D. LOAD FROM data.del OF DEL INSERT INTO tab_a
Answer: D
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